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9x^2-155x-1000=0
a = 9; b = -155; c = -1000;
Δ = b2-4ac
Δ = -1552-4·9·(-1000)
Δ = 60025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{60025}=245$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-155)-245}{2*9}=\frac{-90}{18} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-155)+245}{2*9}=\frac{400}{18} =22+2/9 $
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